Monday 2 September 2013

upload file or image into database in php mysql

//Upload file or image into database in php(up1)
//create table as follows..........

<html>
<head></head>
<body>
<form method="post" enctype="multipart/form-data">
<table width="350" border="0" cellpadding="1"
cellspacing="1" class="box">
<tr>
<td>please select a file</td></tr>
<tr>
<td>
<input type="hidden" name="MAX_FILE_SIZE"
value="16000000">
<input name="userfile" type="file" id="userfile">
</td>
<td width="80"><input name="upload"
type="submit" class="box" id="upload" value=" Upload "></td>
</tr>
</table>
</form>
</body>
</html>
<?php
if(isset($_POST['upload'])&&$_FILES['userfile']['size']>0)
{
$fileName = $_FILES['userfile']['name'];
$tmpName  = $_FILES['userfile']['tmp_name'];
$fileSize = $_FILES['userfile']['size'];
$fileType = $_FILES['userfile']['type'];
$fileType=(get_magic_quotes_gpc()==0 ? mysql_real_escape_string(
$_FILES['userfile']['type']) : mysql_real_escape_string(
stripslashes ($_FILES['userfile'])));
$fp      = fopen($tmpName, 'r');
$content = fread($fp, filesize($tmpName));
$content = addslashes($content);
fclose($fp);
if(!get_magic_quotes_gpc())
{
    $fileName = addslashes($fileName);
}
$con = mysql_connect('localhost', 'root', '') or die(mysql_error());
$db = mysql_select_db('bnr1', $con);
if($db){
$query = "INSERT INTO upload (name, size, type, content ) ".
"VALUES ('$fileName', '$fileSize', '$fileType', '$content')";
mysql_query($query) or die('Error, query failed');
mysql_close();
echo "<br>File $fileName uploaded<br>";
}else { echo "file upload failed"; }
}
?>
end

1 comment:

  1. Hi

    I want to three images can that be done with this code??

    ReplyDelete